Dodgers' Yamamoto has a no-hitter through 6 innings against the Orioles
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Dodgers Orioles Baseball Los Angeles Dodgers starting pitcher Yoshinobu Yamamoto delivers during the third inning of a baseball game against the Baltimore Orioles, Saturday, Sept. 6, 2025, in Baltimore. (AP Photo/Stephanie Scarbrough) (Copyright 2025 The Associated Press. All rights reserved) (Stephanie Scarbrough/AP)
Dodgers Orioles Baseball Los Angeles Dodgers starting pitcher Yoshinobu Yamamoto (18) delivers during the second inning of a baseball game against the Baltimore Orioles, Saturday, Sept. 6, 2025, in Baltimore. (AP Photo/Stephanie Scarbrough) (Copyright 2025 The Associated Press. All rights reserved) (Stephanie Scarbrough/AP)
Dodgers Orioles Baseball Los Angeles Dodgers starting pitcher Yoshinobu Yamamoto delivers during the first inning of a baseball game against the Baltimore Orioles, Saturday, Sept. 6, 2025, in Baltimore. (AP Photo/Stephanie Scarbrough) (Copyright 2025 The Associated Press. All rights reserved) (Stephanie Scarbrough/AP)
BALTIMORE (AP) — Yoshinobu Yamamoto has not allowed a hit through six innings for the Los Angeles Dodgers on Saturday night against the Baltimore Orioles.
The Dodgers lead 3-0.
The 27-year-old right-hander from Japan has allowed two walks and thrown 84 pitches. His career high for pitches since coming to the major leagues is 110.
Yamamoto walked his first two hitters in the third but escaped that jam via a strikeout and a double play. He has struck out seven through six innings.
Yamamoto is coming off a 10-strikeout effort against Arizona on Sunday.
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