MILWAUKEE – Milwaukee Bucks guard Jrue Holiday followed up his biggest game of the season by making a long-term commitment to his new team.
Holiday agreed to a four-year contract extension that would be worth at least $134 million if he exercises his option for the final season. The Bucks announced the agreement Sunday.
“I'm a Buck for life,” Holiday said in a video posted on the Bucks' Twitter account. “Just know that I'm glad to be a part of Bucks Nation. Let's do some big things, man. I'm really excited.”
The announcement came one day after Holiday had a season-high 33 points as well as 11 assists and seven rebounds in a 129-128 victory at Sacramento. Holiday's performance enabled the Bucks to withstand the absence of reigning two-time MVP Giannis Antetokounmpo, who sat out with a sore left knee.
The move represents the latest step in the Bucks’ heavy investment in their trio of Holiday, Antetokounmpo and two-time All-Star Khris Middleton as the franchise chases its first NBA title since 1971.
The Bucks posted the NBA's best regular-season record each of the last two seasons but lost in the Eastern Conference finals in 2019 and in the second round of the playoffs last year. Entering Sunday, Milwaukee owned a 32-17 record and was two games behind Philadelphia and Brooklyn in the East standings.
"Jrue is one of the top guards in the NBA and we are thrilled to sign him to this extension,” Bucks general manager Jon Horst said in a statement. “Adding him to our team has made us better on both ends of the floor. He’s an elite defender and an impactful offensive player with the ability to score, shoot and facilitate.”
Holiday had a $26.7 million player option remaining for the 2021-21 season as part of the five-year, $126 million contract he signed with the New Orleans Pelicans in July 2017.